Title |
Test
Find
Reg Ex for Date with Leap Year
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Expression |
/^(?=\d)(?:(?:(?:(?:(?:0?[13578]|1[02])(\/)31)\1|(?:(?:0?[1,3-9]|1[0-2])(\/)(?:29|30)\2))(?:(?:1[6-9]|[2-9]\d)?\d{2})|(?:0?2(\/)29\3(?:(?:(?:1[6-9]|[2-9]\d)?(?:0[48]|[2468][048]|[13579][26])|(?:(?:16|[2468][048]|[3579][26])00))))|(?:(?:0?[1-9])|(?:1[0-2]))(\/)(?:0?[1-9]|1\d|2[0-8])\4(?:(?:1[6-9]|[2-9]\d)?\d{2}))($|\ (?=\d)))?(((0?[1-9]|1[012])(:[0-5]\d){0,2}(\ [AP]M))|([01]\d|2[0-3])(:[0-5]\d){1,2})?$/ |
Description |
Enter the date in MM/DD/YYYY format. This regular expression validates the day, month and year including the leap year validations. |
Matches |
02/29/2004 |
Non-Matches |
02/31/2004 |
Author |
Rating:
Not yet rated.
Nikhil Shinde
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Source |
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Your Rating |
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Title: Already posted
Name: Michael Ash
Date: 9/17/2007 11:11:20 AM
Comment:
This is almost an identical copy of my regex http://regexlib.com/REDetails.aspx?regexp_id=369 the only difference is this one only allows one type of date field separator (/) where the original gave you three choices. If you are going to modify someone else's work you should give them credit in the "source" field.